SSC CGL 4 Mar 2020 Shift 1 Paper

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Question : 51 of 100

Marks: +1, -0

If sec θ – tan θ = x/y, (0 < x < y) and 0°< θ < 90°, then sinθ is equal to:

$\;{y^{2}−x^{2}}/{x^{2} + y^{2}}$
$\;{x^{2}\;+\;y^{2}}/{y^{2}−x^{2}}$
$\;{2xy}/{x^{2} + y^{2}}$
$\;{x^{2}\;+\;y^{2}}/{2xy}$

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