SSC CGL 4 06 2019 Shift 1 Paper

Question : 70 of 100

Marks: +1, -0

A solid cube of volume 13824 cm

^{3}

is cut into 8 cubes of equal volumes, the ratio of the surface area of the original cube to the sum of the surface areas of three of the smaller cubes is

2 : 3
4 : 3
8 : 3
2 :1

Validate

Solution:

(Volume) original cube

=8 \×

volume of small cubes

13824=8 \×a^{3} \⇒a=12 \ {\cm}

∴ Required ratio

=\ {24 \×24}/{3 \×12 \×12}=\ {4}/{3}

Go to Question:

Prev Question

Next Question