SSC CGL 31 Aug 2016 Paper

Volume of sand = Volume of cylindrical vessel
= $\mathit{\pi }{\mathit{r}}^2\mathit{h}$
= π × ${\left(18\right)}^2$ × 32 cu.cm.
Volume of conical heap
= π × 18 × 18 × 32
⇒ $\frac{1}{3}\mathit{\pi }{\mathit{R}}^2\mathit{H}$ = π × 18 × 18 × 32
⇒ $\frac{1}{3}$ × ${\mathit{R}}^2$ × 24 = 18 × 18 × 32
⇒ ${\mathit{R}}^2$ = $\frac{18\times 18\times 32\times 3}{24}$ = 1296
⇒ R = $\sqrt{1296}$ = 36 cm