If p^2/q^2 + q^2/p^2 = 1, then the value of (p^6 + q^6) is

SSC CGL 30 Aug 2015 Paper

Question : 104 of 200

Marks: +1, -0

p^2/q^2 + q^2/p^2

= 1, then the value of (

p^6 + q^6

) is

Solution:

p^2/q^2 + q^2/p^2

= 1
⇒

{p^4+q^4}/{p^2q^2}

= 1 ⇒

p^4+q^4

p^2q^2

⇒

p^4+q^4 - p^2q^2

= 0 ... (i)
∴

p^6+q^6

(p^2)^3+(q^2)^3

(p^2+q^2)(p^4+q^4-p^2q^2)

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