SSC CGL 3 Sep 2016 Paper

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Question : 64 of 100

Marks: +1, -0

If a = 101, then the value of a (

a^2

– 3a + 3) is :

1000000
1010101
1000001
999999

Solution:

a = 101 (Given)
∴ a (

a^2

– 3a + 3)
=

a^3 – 3a^2

+ 3a – 1 + 1
=

(a – 1)^3

+ 1 =

(100)^3

+ 1
= 1000001

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