SSC CGL 26 Oct 2014 Shift 2 Paper

Question : 137 of 200

Marks: +1, -0

If x [–2 {–4 (–a)}] + 5 [–2 {–2 (– a)}] = 4a, then x =

–2
–3
–4
–5

Solution:

x [– 2 {– 4 (– a)}] + 5 [– 2 { – 2 (– a) } ] = 4 a
⇒ x × (– 8 a) + 5 × (– 4 a) = 4 a
⇒ x × (– 2) + 5 × (– 1) = 1
⇒ 2 x + 5 = – 1
⇒ 2 x = – 5 – 1 = – 6
⇒ x =

-6/2

= - 3

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