‘O’ is the centre of the circle, AB is a chord of the circle, OM ^ AB. If AB = 20 cm, OM = 2 \sqrt{11} cm, then radius of the circle is

SSC CGL 26 Oct 2014 Shift 2 Paper

Question : 120 of 200

Marks: +1, -0

‘O’ is the centre of the circle, AB is a chord of the circle, OM ^ AB. If AB = 20 cm, OM = 2

√{11}

cm, then radius of the circle is

Solution:

AB = 20 cm.
AM = MB = 10 cm.
OM = 2

√{11}

cm.
∴ Radius OA =

√{OM^2+AM^2}

√{(2√{11})^2+10^2}

√{4×11+100}

√{44+100}

√{144}

= 12 cm.

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