SSC CGL 26 Oct 2014 Shift 2 Paper

Single equivalent discount for two successive discounts
= $\left(\mathit{x}+\mathit{y}-\frac{\mathit{x}\mathit{y}}{100}\right)$ %
= $\left(\frac{25}{2}+10-\frac{25\times 10}{200}\right)$ %
= (12.5 + 10 – 1.25 )%
= 21.25 %
If the marked price of the plate be Rs. x, then
= (100 – 21.25 ) % of x = 6300
⇒ x × $\frac{78.75}{100}$ = 6300
⇒ x = $\frac{6300\times 1000}{78.75}$ = Rs. 8000