SSC CGL 26 Oct 2014 Shift 1 Paper

Question : 142 of 200

Marks: +1, -0

The heights of two similar right-angled triangles Δ LMN and Δ OPQ are 48 cm and 36 cm. If OP = 12 cm, then LM is

Solution:

∠ L = ∠ O ; ∠ M = ∠ P and
∠ N = ∠ Q
∴ Δ LMN ~ Δ OPQ
∴

{NL}/{OQ}

{LM}/{OP}

⇒

{48}/{36}

{LM}/{12}

⇒ 36 × LM = 12 × 48
⇒ LM =

{12×48}/{36}

= 16 cm

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