SSC CGL 26 Oct 2014 Shift 1 Paper

Question : 101 of 200

Marks: +1, -0

The area of the iron sheet required to prepare a cone 24 cm high with base radius 7 cm is
(Taake π =

{22}/7

)

Solution:

Slant height of cone (l)
=

√{7^2+24^2}

√{49+576}

√{625}

= 25 cm
∴ Total surface area of cone
= πrl +

πr^2

= πr (l + r)
=

{22}/7

× 7 × (25 + 7)
= 22 × 32 = 704 sq. cm.

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