SSC CGL 23 Aug 2021 Shift 1 Paper

593 ab is divisible by 3,7 and 11 Take maximum 5 digit number by Putting $\mathit{a}\mathit{b}=99$
Then LCM of 3,7 and $11=231$
We get $59399-32=59367$
[which is divisible by 3,7 and 11]
$\therefore$ The value of $\mathit{a}=6,\mathit{b}=7$
So, $\left({\mathit{a}}^2-{\mathit{b}}^2+\mathit{a}\mathit{b}\right)=\left(6^2-7^2+6\times 7\right)$
$=\left(36-49+42\right)=29$
Hence, the value of ${\mathit{a}}^2-{\mathit{b}}^2+\mathit{a}\mathit{b}$ is 29 .