SSC CGL 23 Aug 2021 Shift 1 Paper

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Question : 18 of 100

Marks: +1, -0

The numbers

{A}

and

{B}

are such that the sum of

3 \%

of

A

and

6 \%

of

B

is four-fifths of the sum of

4 \%

of

A

and

6 \%

of

B

. Find the ratio of

A+B

and

{A}- {B}

$5: 6$
$7: 5$
$4: 5$
$6: 5$

Solution:

According to the questions,

3 \%

of

A+6 \%

of

B=\;{4}/{5}

(4 \%

of

A+6 \%

of

B

)

⇒ \;{3}/{100} × A+\;{6}/{100}\;× B

= \;\; \;{4}/{5}(\;{4}/{100} × A+\;{6}/{100} × B)

⇒ \;{1}/{100}(3 A+6 B) \;\; =\;{4}/{5 × 100}(4 A+6 B)

⇒ \;\; 15 A+30 B \;\; =16 A+24 B

⇒ \;\; 16 A-15 A \;\; =30 B-24 B

⇒ \;\; A \;\; =6 B

\;{A}/{B} \;\; =\;{6}/{1}

Ratio of

\;{A+B}/{A-B}=\;{6+1}/{6-1}=\;{7}/{5}

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