The area of a quadrant of a circle is \frac{\pi}{9} {m}^{2}. Its radius (in {m} ) is equal to

SSC CGL 20 Aug 2021 Shift 1 Paper

Question : 74 of 100

Marks: +1, -0

The area of a quadrant of a circle is

\;{π}/{9} {m}^{2}

. Its radius (in

{m}

) is equal to

Solution:

Given, area of quadrant of circle

=\;{π}/{9} {m}^{2}

⇒ \;\; \;{π r^{2}}/{4}=\;{π}/{9}

⇒ \;\; r^{2}=\;{4}/{9} ⇒ r=√{\;{4}/{9}}

∴ \;\; r=\;{2}/{3} m .

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