SSC CGL 2 Sep 2016 Shif 2 Paper

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Question : 71 of 100

Marks: +1, -0

If r sinq =

√3

and r cosθ = 1, then values of r and θ are : (0° < θ < 90°)

r = 1, θ = 30°
r = $1/2$ , θ = 30°
r = $√3$ , θ = 30°
r = 2, θ = 60°

Solution:

r sin θ =

√3

r cos θ = 1
On squaring and adding

r^2sin^2 θ + r^2 cos^2 θ

= 3 + 1
⇒

r^2(sin^2 θ + cos^2 θ)

= 4
⇒

r^2

= 4 ⇒ r =

√4

= 2
Again,

{rsinθ}/{rcosθ}

=

√3

⇒ tan θ =

√3

= tan 60°
⇒ θ = 60°

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