SSC CGL 2 Sep 2016 Shif 2 Paper

Question : 60 of 100

Marks: +1, -0

The vertical angle A of an isosceles triangle ΔABC is three times the angle B of it. The measure of the angle A is

Solution:

In ΔABC,
AB = AC
∴ ∠B = ∠C
Since ∠A + ∠B ∠C = 180°
∴ ∠A +

{ϑA}/3 + {∠A}/3

= 180°
⇒

{3∠A+∠A+∠A}/3

= 180°
⇒

{5∠A}/3

= 180°
⇒ ∠A =

{180°×3}/5

= 108°

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