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Question : 136 of 200
Marks:
+1,
-0
Solution:
tan 1° . tan 2° . tan 3° ... tan 89°
= (tan 1° . tan 89°) (tan 2°. tan88°) ... tan 45°
= (tan 1°. tan(90° – 1°) ) (tan 2° tan (90° – 2°) .. tan 45°
= (tan 1° . cot 1°) (tan 2°. cot 2°) .. tan 45°
= 1.1..1. = 1
[tan (90° – θ) = cot θ]
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