SSC CGL 19 Oct 2014 Shift 2 Paper

Question : 112 of 200

Marks: +1, -0

Two numbers A and B are such that the sum of 5% of A and 4% of B is

2/3

rd of the sum of 6% of A and 8% of B. The ratio A : B is

Solution:

Numbers
⇒ A and B
∴

{A×5}/{100}+{B×4}/{100}

2/3 ({A×6}/{100}+{B×8}/{10})

⇒ 5A + 4B =

{12A+16B}/3

⇒ 15A + 12B = 12A + 16B
⇒ 15A – 12A = 16B – 12B
⇒ 3A = 4B
⇒

A/B

4/3

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