If A = 10° , what is the value of: {12 \sin 3 A+5 \cos (5 A-5^{\circ}) }/{9 \sin \frac{9 A}{2}-4 \cos (5 A+10^{\circ}) } ?

Correct Answer is : 62+5(9−22)

{6 \sqrt{2}+5}/{(9-2 \sqrt{2})}

{6 \sqrt{2}-5}/{(9-2 \sqrt{2})}

{(9-2 \sqrt{2})}/{6 \sqrt{2}+5}

{6 \sqrt{2}+5}/{(9+2 \sqrt{2})}

SSC CGL 18 Apr 2022 Shift 3 Paper

Question : 53 of 100

Marks: +1, -0

If A = 10° , what is the value of:

\;{12 sin \;3 A+5 \cos (5 A-5^{∘}) }/{9 sin \;\;{9 A}/{2}-4 \cos (5 A+10^{∘}) } ?

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