SSC CGL 17 Aug 2021 Shift 3 Paper

Question : 67 of 100

Marks: +1, -0

In a circle, a

10 \mathrm{~cm}

long chord is at a distance of

12 \mathrm{~cm}

from the centre of the circle. Length of the diameter of the circle

(

\mathrm{cm})

Solution:

Given, chord

A B=10 {cm}

Distance between chord and circle centre is

12 {cm}

.
In

△ O P B

, by using Pythagoras Theorem,

⇒(O B)^{2} \;\; =(O P)^{2}+(P B)^{2}

⇒(O B)^{2} \;\; =(12)^{2}+(5)^{2}( ∵ A P+P B=10)

(O B)^{2} \;\; =144+25

⇒ \;\; O B \;\; =√{169} ⇒ O B=13 {cm}

O B

is radius of circle
So, diameter

=2 ×

radius

=2 × 13=26 {cm} \;\text ". "\;

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