SSC CGL 17 Aug 2021 Shift 1 Paper

Question : 60 of 100

Marks: +1, -0

A certain sum becomes

₹ 13650

15 \%

p.a. simple interest after

2 {yr}

. What will be the amount (in ₹) of the same sum after 1 yr at the same rate of interest, if the interest is compounded half yearly? (nearest to a ₹)

Solution:

Given,

A=13650, R=15 \%

T=2 {yr}

A=P+\;{P × R × T}/{100}=P+\;{P × 15 × 2}/{100}

⇒ \;\; 13650=1.3 P

⇒ \;\; P=10500

Same principal,

A=?, T=1 {yr}=2

half

{yr}

R=15 \%

using

{Cl}

method,
Amount

=P(1+\;{R}/{100})^{T}

For half yearly time let

2 {yr}

\;\text " Rate "\; \;\; =\;{15}/{2} \%,

A \;\; =10500(1+\;{15}/{2 × 100})^{2}

\;\; =10500 ×(\;{43}/{40})^{2}

\;\text " Amount "\; \;\; =10500 × 1.15

\;\; =12134.06 ≈ 12134 .

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