If \sin \\theta = 20/29 , then what is the value of cos θ ?

SSC CGL 17 Aug 2017 Shift 1 Paper

Question : 71 of 100

Marks: +1, -0

\sin \θ = 20/29

, then what is the value of cos θ ?

Solution:

According to the question,

In right angled ΔABC,

B C^{2}=A C^{2}-B A^{2}=29^{2}-20^{2}

=(29+20)(29-20)=49 × 9

∴

B C=√{49 × 9}=7 \× 3=21

\∴ \cos \θ= {B C}/{A C}= {21}/{29}

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