SSC CGL 16 Aug 2015 Shift 2 Paper

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Question : 47 of 200

Marks: +1, -0

Kailash walks 3 kms to East and turns South and walks 4 kms. Again turns West and walks 6 kms. How far is he from the starting point?

6 kms
7 kms
3 kms
5 kms

Solution:

AD =

√{(AE)^2+(DE)^2}

=

√{(4)^2+(3)^2}

=

√{16+9}

=

√{25}

= 5 km

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