SSC CGL 16 Aug 2015 Shift 2 Paper

Question : 149 of 200

Marks: +1, -0

A train leaves station A at 5 AM and reaches station B at 9 AM on the same day. Another train leaves station B at 7 AM and reaches station A at 10:30 AM on the same day. The time at which the two trains cross each other is :

8 : 26 AM
7: 36 AM
7: 56 AM
8 AM

Validate

Solution:

Here distance is constant.
∴ Speed α

1/{\Time}

∴ Ratio of the speeds of A and
B =

{7/2}/4

= 7 : 8
∴ A’s speed = 7x kmph (let)
B’s speed = 8x kmph
∴ AB = 7x × 4 = 28x km.
Let both trains cross each other after t hours from 7 a.m.
According to the question,
7x (t + 2) + 8x × t = 28x
⇒ 7t + 14 + 8t = 28
⇒ 15t = 28 – 14 = 14
⇒ t =

{14}/{15}

hours
=

({14}/{15} × 60)

minutes
= 56 minutes
∴ Required time = 7 : 56 a.m.

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