SSC CGL 16 Aug 2015 Shift 2 Paper

Question : 132 of 200

Marks: +1, -0

Two alloys contain tin and iron in the ratio of 1 : 2 and 2 : 3. If the two alloys are mixed in the proportion of 3 : 4 respectively (by weight), the ratio of tin and iron in the newly formed alloy is :

10 : 21
13 : 22
14 : 25
12 : 23

Validate

Solution:

Let 3kg of first alloy and 4 kg of second alloy be mixed together.
∴ In 3 kg of mixture,
Tin = 1 kg.
Iron = 2 kg.
In 4 kg of mixture,
Tin =

2/5

× 4 =

8/5

= 1.6 kg
Iron =

3/4

× 4 =

{12}/5

= 2.4 kg
∴ Required ratio
= (1 + 1.6) : (2 + 2.4) = 2.6 : 4.4
= 13 : 22

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