SSC CGL 16 Aug 2015 Shift 2 Paper

Let A, B, C, D and E in kg. represent their respective weights. Then,
∴ A + B + C = 84 × 3 = 252 kg.
A + B + C + D = 80 × 4 = 320 kg.
∴ D = (320 – 252) kg. = 68 kg.
E = 68 + 3 = 71 kg.
B + C + D + E = 79 × 4 = 316 kg.
Now,
(A + B + C + D) – (B + C + D + E) = 320 – 316
⇒ A – E = 4 kg.
⇒ A = 4 + E = 4 + 71 = 75 kg.