SSC CGL 16 Aug 2015 Shift 1 Paper

Question : 150 of 200

Marks: +1, -0

If sec θ + tan θ = p, (p ≠ 0) then sec θ is equal to

Solution:

sec θ + tan θ = p.....(i)
Since

sec^2θ – tan^2θ

= 1
⇒ (secθ + tanθ) (secθ – tanθ) = 1
⇒ secθ – tanθ =

1/p

... (iii)
On adding both the equations,
2 secq = p +

1/p

⇒ sec θ =

1/2 (p+1/p)

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