SSC CGL 16 Aug 2015 Shift 1 Paper

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Question : 128 of 200

Marks: +1, -0

The value of

sin^2

22° +

sin^2

68° +

cot^2

30° is

4
3
$3/4$
$5/4$

Solution:

sin^2

22° +

sin^2

68° +

cot^2

30°
=

sin^2

22° +

sin^2

(90° - 22°) +

(√3)^2

=

sin^2

22° +

cos^2

22° + 3
[Since

sin^ θ + cos^2 θ

= 1]
= 1 + 3 = 4

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