SSC CGL 16 Aug 2015 Shift 1 Paper

Question : 109 of 200

Marks: +1, -0

A kite is flying at the height of 75m from the ground. The string makes an angle θ (where cot θ =

8/{15}

) with the level ground. Assuming that there is no slack in the string the length of the string is equal to :

Solution:

A = Position of kite
AC = length of string
AB = 75 metre
cot θ =

8/{15}

∴ cosec θ =

√{1+cot^2 θ}

√{1+(8/{15})^2}

√{1+{64}/{225}}

√{{225+64}/{225}}

√{{289}/{225}}

{17}/{15}

∴ sin θ =

{15}/{17}

From ΔABC
sin θ =

{AB}/{AC}

⇒

{15}/{17}

{75}/{AC}

⇒ AC × 15 = 17 × 15
⇒ AC =

{17×15}/{15}

= 85 metre

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