SSC CGL 13 Jun 2019 Shift 1 Paper

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Question : 66 of 100

Marks: +1, -0

If

3 \sin \θ=2 \cos \θ,

then

\ {4 \sin \θ-\cos \θ}/{4 \cos \θ+\sin \θ}

is equal to:

$5/7$
$5/8$
$5/14$
$5/11$

Solution:

3 \sin \θ=2 \cos \θ

\sin \θ=2k,\cos \θ=3k

Now,

\ {4 \sin \θ-\cos \θ}/{4 \cos \θ+\sin \θ}

=\ {8 k-3 k}/{12 k+2 k}=\ {5}/{14}

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