SSC CGL 13 Jun 2019 Shift 1 Paper

Question : 62 of 100

Marks: +1, -0

ΔABC ∼ ΔEDF and ar (ΔABC) : ar (ΔEDF) = 1 : 4. If AB = 7 cm, BC = 8 cm and CA = 9 cm, then DF is equal to:

Solution:

\ {\ar \Δ\ABC}/{\ar \Δ\DEF }=\ (\ {B C}/{D F}\ )^{2}

=\ {1}/{2}=\ {8}/{D F}

⇒D F=16 \ {\cm}

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