SSC CGL 12 Jun 2019 Shift 2 Paper

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Question : 65 of 100

Marks: +1, -0

If

\ {\cosec} 3 \θ=\sec \ (20°+2 \θ\ ),

then

\θ

is equal to:

30°
20°
15°
14°

Solution:

\ {\cosec} 3 \θ=\sec \ (20°+2 \θ\ )

\⇒(3 \θ)+(20+2 \θ)=90

\⇒5 \θ=70

\⇒\θ=14°

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