SSC CGL 12 Jun 2019 Shift 2 Paper

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Question : 62 of 100

Marks: +1, -0

If

3 \sin \θ=4 \cos \θ,

then

\tan ^{2} \θ+\sin \θ-

\cos \θ

is equal to:

$88/45$
2
$89/45$
$17/9$

Solution:

3 \sin \θ=4 \cos \θ

\tan \θ=\ {4}/{3}=\ {P}/{B} ; H=5

Now,

\tan ^{2} \θ+\sin \θ-\cos \θ

\⇒\ {16}/{9}+\ {4}/{5}-\ {3}/{5}

\⇒\ {89}/{45}

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