SSC CGL 12 Jun 2019 Shift 1 Paper

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Question : 68 of 100

Marks: +1, -0

The value of

{\sin 44°}/{\cos 46°}+\sin ^{2} 60°-\cos ^{2} 45°

+\sec 60°

isequal to:

$13/4$
$11/3$
$11 /4$
$7/4$

Solution:

\ {\cos (90-46)}/{\cos 46}+\ {3}/{4}-\ {1}/{2}+2

=\ {\cos 46}/{\cos 46}+\ {3-2}/{4}+2

=1+\ {1}/{4}+2

=3+\ {1}/{4}=\ {13}/{4}

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