The value of: 3.8+(8.2 \\div4.1 \\times2)-4 \\times3 \\div1.2

SSC CGL 12 Jun 2019 Shift 1 Paper

Question : 64 of 100

Marks: +1, -0

The value of:

3.8+(8.2 \÷4.1 \×2)-4 \×3 \÷1.2

Solution:

3.8+\ (\ {8.2}/{4.1} \×2\ )-4 \×\ {3}/{1.2}

=3.8+(2 \×2)-10

=7.8-10=-2.2

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