SSC CGL 12 Jun 2019 Shift 1 Paper

Question : 58 of 100

Marks: +1, -0

ΔABC ~ ΔRQP and PQ = 10 cm, QR = 12 cm and RP = 16cm. If ar(ΔPQR) : ar(ΔABC) =

9/4

, then BC is equal to:

Solution:

\ {\Δ\PQR}/{\Δ\ABC}=\ {9}/{4}=\ {Q P^{2}}/{B C^{2}}

\ {10}/{B C}=\ {3}/{2}

B C=\ {20}/{3} \ {\cm}

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