SSC CGL 12 Aug 2017 Shift 1 Paper

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Question : 70 of 100

Marks: +1, -0

Ifis acute angle and

\tan \θ-\cot \θ=0,

then what is thevalue of

\tan ^{26} \θ+\cot ^{100} \θ ?

-2
0
1
2

Solution:

\tan \θ=\cot \θ

⇒

\tan \θ=\tan (90°-\θ)

⇒

\θ=90° -\θ

⇒

2 \θ=90°

∴

\θ=45°

\tan ^{26} \θ+\cot ^{100} \θ

=\tan ^{26} 45°+\cot ^{100} 45°

=(1)^{26}+(1)^{100}=2

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