SSC CGL 11 Jun 2019 Shift 1 Paper

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Question : 70 of 100

Marks: +1, -0

If

\tan 4 \θ=\cot \ (2 \θ+30°),

then

\θ

is equal to:

15°
10°
20°
25°

Solution:

\tan 4 \θ=\cot \ (2 \θ+30°)

\⇒\cot (90-4 \θ)=\cot \ (2 \θ+30°)

Now,

90-4 \θ=2 \θ+30°

\θ=10°

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