SSC CGL 11 Jun 2019 Shift 1 Paper

Question : 64 of 100

Marks: +1, -0

In ΔABC, AD is a median and P is a point on AD such that AP : PD = 3 : 4. Then ar(ΔAPB) : ar(ΔABC) is equal to:

Solution:

Let

\Ar(\Δ\ABC)=14 \ {\sq},

units
Now, AD (median) divide

\Δ {\ABC}

into two equalareas
And, area is divided in the ratio of bases.

\∵ {\Ar(\Δ \APB)}/{\Ar(\Δ\ABC)}=\ {3}/{14}

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