SSC CGL 11 Jun 2019 Shift 1 Paper

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Question : 52 of 100

Marks: +1, -0

If

\cot \θ=\ {3}/{4},

then

\sin \θ+\cos \θ-\tan \θ

is equal to:

$-1/20$
$2/15$
$1/20$
$1/15$

Solution:

\cot \θ=\ {3}/{4}=\ {B}/{P}

\cos \θ+\sin \θ-\tan \θ

=\ {3}/{5}+\ {4}/{5}-\ {4}/{3}

=\ {9+12-20}/{15}=\ {1/{15}

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