SSC CGL 11 Aug 2017 Shift 1 Paper

Question : 68 of 100

Marks: +1, -0

In the given figure, ABC is an equilateral triangle. If the area of bigger circle is 1386 cm

^{2}

, then what is the area (in cm

^{2}

) of smaller circle ?

Solution:

Area of bigger circle

= πr^2

1386=22/7 ×R^2

⇒

R^2={1386 ×7}/22

⇒

R^2=63 ×7

⇒

R=√{3 ×3 ×7 ×}

∴

R=3 ×7=21\cm

Radius of smaller circle

=\πr^2=22/7 ×7^2

=22 ×7=154\cm^2

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