SSC CGL 11 Aug 2017 Shift 1 Paper

According to the question,
A + B + C = 60500 ...(i)
⇒ $\mathit{A}=\left(\mathit{B}+\mathit{C}\right)\times \frac{2}{9}$
⇒ $9\mathit{A}=2\left(\mathit{B}+\mathit{C}\right)$
⇒ $\mathit{B}+\mathit{C}=\frac{9\mathit{A}}{2}$
From Eq. (i),
$\mathit{A}+\frac{9\mathit{A}}{2}=6050$
⇒ $\frac{11\mathit{A}}{2}=60500$
⇒ $\mathit{A}=\frac{60500\times 2}{11}$
∴ $\mathit{A}=11000$
Again, $\mathit{B}=\left(\mathit{A}+\mathit{C}\right)\times \frac{3}{7}$
$\frac{7\mathit{B}}{3}=\mathit{A}+\mathit{C}$
From Eq. (i),
$\frac{7\mathit{B}}{3}+\mathit{B}=60500$
⇒ $\frac{10\mathit{B}}{3}=60500$
⇒ $\mathit{B}=\frac{60500\times 3}{10}$
∴ $\mathit{B}=18150$
⇒ $\mathit{C}=60500-\left(\mathit{A}+\mathit{B}\right)$
⇒ $\mathit{C}=60500-\left(11000+18150\right)$
∴ $\mathit{C}=60500-29150=\mathrm{₹}31350$