SSC CGL 10 Jun 2019 Shift 2 Paper

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Question : 53 of 100

Marks: +1, -0

When

2 \sin ^{2} \θ=3 \cos \θ,

and

0 \ ≤ \θ\ ≤ 90°,

then

\theta=?

45°
30°
90°
60°

Solution:

2 \sin ^{2} \θ=3 \cos \θ

Go through option, only option (d) satisfies

2 \sin ^{2} \θ60°=3 \cos 60°

\⇒2 \× \ {3}/{4}=3 \× \ {1}/{2}

So the value is

\θ=60°

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