If a^{2}+b^{2}+c^{2}+27=6(a+b+c), then what is the value of \\sqrt^3{a^{3}+b^{3}-c^{3}} ?

SSC CGL 10 Jun 2019 Shift 1 Paper

Question : 74 of 100

Marks: +1, -0

a^{2}+b^{2}+c^{2}+27=6(a+b+c),

then what is the value of

\√^3{a^{3}+b^{3}-c^{3}} ?

Solution:

a^{2}+b^{2}+c^{2}-2(3 a+3 b+3 c)+27=0

\⇒a=3, b=3, C=3

Now,

\√^3 {a^{3}+b^{3}-c^{3}}

\⇒\√^3 {3^{3}+3^{3}-3^{3}}=3

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