SSC CGL 1 Sep 2016 Paper

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Question : 62 of 100

Marks: +1, -0

If sin θ =

√3/2

and 0° < θ < 9° , then the value of tan (θ - 15°) is

1
$√3$
$1/√3$
$√2$

Solution:

sin θ =

√3/2

= sin 60°
⇒ θ = 60°
∴ tan (θ - 15°)
= tan (60° - 15°)
= tan 45°
= 1

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