If f(x) = \{ \table 1+x, 0\leq x \leq2; 3-x, 2< x \leq 3 then f[f(x)] is

Correct Answer is : f[f(x)]={2+x0≤x≤12−x1<x≤24−x2<x≤3

f[f(x)] = \{ \table 2+x, 0\leq x \leq 1; 2-x, 1< x \leq 2; 4-x, 2< x \leq 3

f[f(x)] = \{ \table 2+x, -1 \leq x \leq 1; 2-x, 1< x \leq 2;4-x, 2< x \leq3

f[f(x)] = \{ \table 2+x,0 \leq x \leq 1; 2-x, 1\leq x \leq 2; 4-x, 1 \leq x \leq 3; x, 0\leq x \leq1

f[f(x)] = \{ \table 2+x, -1 \leq x \leq 1; 2-x, 1< x \leq 2; 4-x, 2 \leq x < 3

SRMJEE 2019 Paper with key

Question : 74 of 140

Marks: +1, -0

If f(x)={

1+x	0≤x≤2
3−x	2<x≤3

then f[f(x)] is

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