SRMJEE 2018 Paper with key

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Question : 81 of 147

Marks: +1, -0

If |

1	x	x2
x	x2	1
x2	1	x

|=7 and ∆=|

x3−1	0	x−x4
0	x−x3	x3−1
x−x4	x3−1	0

|, then

∆ = -9
∆ = 7
∆ = 49
∆ = 343

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