SRMJEE 2017 Paper with key

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Question : 77 of 155

Marks: +1, -0

If [

√3

2

+(

1

2

)t

√3

2

−(

1

2

)t

]120=p+iq, then

p=cos20°,q=sin20°
p=−cos20°,q=−sin20°
p=cos20°,q=−sin20°
p=1,q=0

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