Find the sum of the series. 243+324+432+....... to {n} terms

Correct Answer is : 36(4n3n−1)

3^{6}( {4^{ {n}}}/{3^{ {n}}}-1)

3^{4}( {4^{ {n}}}/{3^{ {n}}}-1)

Sequence and Series

Question : 41 of 86

Marks: +1, -0

Find the sum of the series.

243+324+432+.......

{n}

terms

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