I. x^2 − (16)^2 = (23)^2 − 56 II.y^{1/3} − 55 + 376 = (18)^2

SBI PO Prelims Model Paper 12

Directions (Q. 36 to 40): In the following questions two equations numbered I and II are given.You have to solve both the equations and give answer if
1) x > y
2) x ≥ y
3) x < y
4) x ≤ y
5) x = y or the relationship cannot be established

Question : 37 of 95

Marks: +1, -0

I. x2−(16)2=(23)2−56
II.y

−55+376=(18)2

Validate

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