SBI PO 10 July 2016 Paper

I. 12x2 – 23x + 11 = 0
⇒ 12x2 – 12x – 11x + 11 = 0
⇒ 12x (x – 1) – 11 (x – 1) = 0
⇒ (x – 1) (12x – 11) = 0
⇒ x = 1 or

11

12

II. 21y2 – 20y + 4 = 0
⇒ 21y2 – 14y – 6y + 4 = 0
⇒ 7y (3y – 2) – 2 (3y – 2) = 0
⇒ (3y – 2) (7y – 2) = 0
⇒ y =

2

3

or

2

7

Clearly, x > y